Question 719519
Find three consecutive integers such that the sum of the first and third is 63.


Let the three consecutive integers be:

n + (n + 1) + (n + 2)

Add the first and third:

n + n + 2 = 63

2n + 2 = 63

Subtract 2 from each side of the equation:

2n + 2 - 2 = 63 - 2

Combine like terms:

2 - 2 = 0

63 - 2 = 61

Therefore:

2n = 61

Divide each side by 2

2n/2 = 61/2

n = 30.5

n + 1 = 31.5

n + 2 = 32.5

Therefore the first and third add up to 63

n + n + 2 = 30.5 + 32.5 = 63

Therefore the three consecutive integers are:

30.5, 31.5 and 32.5