Question 719545
Let "n" represent the first number of the three consecutive numbers.

4(n+1) = n+(n+2)
4n +4 = n+(n+2)  Use the Distributive property
3n + 4 = n + 2   Subtract common terms
2n + 4 = 2       Subtract common terms
2n = -2          Subtract 4 from both sides
--------         Divide by 2
   2
n = -1           Solution

Therefore, the three consecutive integers would be n, n+1, and n+2 (-1, 0, 1)
Just remember that three consecutive numbers or integers can be defined as a variable added by 1,2,3... whatever. Hope this helped!