<PRE><B>Question 719265</B>
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Multiply the first equation by 2.  Notice that both equations are now identical.  Hence, any ordered pair that satisfies one of the equations satisfies the other.  So the number of solutions of one of the equations is the number of solutions of the system.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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