Question 719267
log (2,x)+log(x)=11
Is it 2 different bases?
{{{log (2,x)+log(x)=11}}}
{{{log(2,x) = log(x)/log(2)}}}
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{{{log(x)/log(2) + log(x) = 11}}}
{{{log(x)*(1 + 1/log(2)) = 11}}}
{{{log(x) = 11/(1 + 1/log(2))}}}
{{{x = 10^(11/(1 + 1/log(2)))}}}
w/o formatting:  x = 10^(11/(1 + 1/log(2)))
x =~ 350.8814