Question 719217
How do you put y= -8x^2+ 3 into vertex form?
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Vertex form of equation for a parabola: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex, A is a multiplier which affects the slope or steepness of the curve.
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Given equation is already in vertex form with: 
vertex at (0,3) and A=-8