Question 719182
<ol><li>Draw a right triangle and pick one of the acute angles to be {{{theta}}}, as instructed in the problem.</li><li>Rewrite the 15 in the csc equation as a fraction:
{{{csc(theta) = 15/1}}}.</li><li>Since the ratio for csc is hypotenuse over opposite, make the hypotenuse of the triangle be a 15 (the numerator of 15/1) and make the side opposite to {{{theta}}} be a 1 (the denominator of 15/1)</li><li>Use the Pythagorean Theorem to find the side which is adjacent to {{{theta}}}. (Hint: It will be a square root.)</li><li>Now that you have all three sides, the hypotenuse and the sides which are opposite to and adjacent to {{{theta}}}, you can now set up the ratios for the other five trig functions.</li><li>Some of the ratios from the previous step will have the square root from step 4 in the denominator. Rationalize these fractions by multiplying the numerator and denominator of the fraction by the square root.</li></ol>