Question 63146
THE POLYNOMIAL f(x) DIVIDED x-3 RESULTS IN A QUOTIENT OF x2+3x-5 WITH A REMAINDER OF 2. FIND f(3).
:
The problem as I understand it:
{{{f(x)/(x-3)}}} = x^2 + 3x - 5, Remainder of 2/(x-3)
:
Find f(x)
f(x) = (x-3) * (x^2 + 3x - 5)
:
Used "...." to keep things lined up
...........x^2 + 3x - 5
........................x - 3
--------------------
.........-3x^2 - 9x + 15
x^3 + 3x^2 - 5x
--------------------
x^3 + 0x^2 -14x + 15
add remainder.......+ 2 
----------------------
..........x^3 - 14x + 17 = f(x)
:
:
Find f(3) 
f(3) = 3^3 - 14(3) + 17
f(3) = 27 - 42 + 17
f(3) = 2