<PRE><B>Question 718942</B>
normal distribution with a mean of 61 and standard deviation of 5, how to calculate the standard score equivalents for 
x           x       z        t
66
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Not sure what you mean be repeating the x value.
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z(66) = (66-61)/5 = 5/5 = 1
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t(66) = is the same as z(66)
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Cheers,
Stan H.
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