Question 718935
if the probility of being hospitalized during a year is 0.1, find the probablity that no one in a family of five will be hospitalized in a year?
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P(an member of the family is not hospitalized) = 0.9
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P(none of 5 are hospitalized) = 0.9^5 = 0.5905
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Cheers,
Stan H.
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