Question 718811
<font face="Times New Roman" size="+2">


You can't "solve" it because you have no relational operator, i.e. =, <, >, *[tex \LARGE \leq], or *[tex \LARGE \geq].  I will then presume that you want to factor it.


Multiply the lead coefficient by the constant term: 15 times 2 is 30.


Perform the prime factorization of 30:  2 X 3 X 5.  So the two-integer factors of 30 must be 6 X 5, 10 X 3, 15 X 2, or 30 X 1.  Examine these pairs for a set that sums to the first degree term coefficient, i.e. 31.  Looks like 30 and 1, right?


Rewrite the 1st degree term as a pair of terms that sum to *[tex \LARGE 31x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 15x^2\ +\ 30x\ +\ x\ +\ 2]


Factor by grouping:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 15x(x\ +\ 2)\ +\ (x\ +\ 2)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (15x\ +\ 1)(x\ +\ 2)]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>