Question 718650
{{{x^2+2x-4=0}}}
This will not factor. So we must use the Quadratic Formula:
{{{x = (-(2) +- sqrt((2)^2-4(1)(-4)))/2(1)}}}
Simplifying...
{{{x = (-(2) +- sqrt(4-4(1)(-4)))/2(1)}}}
{{{x = (-(2) +- sqrt(4+16))/2(1)}}}
{{{x = (-(2) +- sqrt(20))/2(1)}}}
{{{x = (-2 +- sqrt(20))/2}}}
{{{x = (-2 +- sqrt(4*5))/2}}}
{{{x = (-2 +- sqrt(4)*sqrt(5))/2}}}
{{{x = (-2 +- 2*sqrt(5))/2}}}
{{{x = (2(-1 +- sqrt(5)))/2}}}
{{{x = (cross(2)(-1 +- sqrt(5)))/cross(2)}}}
{{{x = -1 +- sqrt(5)}}}
which is short for:
{{{x = -1 + sqrt(5)}}} or {{{x = -1 - sqrt(5)}}}