Question 718696
You're good so far with:
{{{x-6 = log(10, (y))}}}
The next step is to rewrite the equation in exponential form. (That is how you get rid of the log.) In general {{{log(a, (p)) = q}}} is equivalent to {{{p = a^q}}}. Using this pattern on your equation we get:
{{{10^((x-6)) = y}}}
This is the inverse.