Question 718532
Let the distance from Hazelton when they meet be x
Let time taken by Mike be y
speed mike =18m/h

Distance = speed * time

x= 18y

Katie speed = 30m/h
time = y-(1/3) hours

distance =x
x= (y-1/3) *30
=((3y-1)/3 )*30

equate both

18y=30y-10

-12y= -10

y= 5/6 hours

So Mike takes 5/6 hours

x=18y
x= 18*5/6
=15 miles

so they are 100-15 = 85 miles from Pleasantville