Question 718268
1.) (x^2-1)^4(2x)-x^2(4)(x^2-1)^3(2x) divided by (x^2-1)^8
The first step is very good (because a lot of people have trouble seeing how to factor like this):
2x(x^2-1)^3[(x^2-1)-4x^2}] divided by (x^2-1)^8<br>
But you went wrong with:
2x(x^2-1)^3-4x^2 divided by (x^2-1)^7
Apparently you canceled the (x^2-1) in the brackets with one of the eight (x^2-1)'s in the denominator. The error is that <u>only</u> factors can be canceled and the (x^2-1) you canceled in the numerator is not a factor of the numerator!<br>
What you should do is combine like terms in the bracket:
2x(x^2-1)^3[-3x^2-1] divided by (x^2-1)^8
Then you cancel all three (x^2-1)'s in the numerator (next to the 2x) with three of the eight (x^2-1)'s in the denominator:
2x[-3x^2-1] divided by (x^2-1)^5