Question 63328
write the slope-intercept form of and equation of the line that passses through the given point and is parallel to the graph of each equation. 
(4,-6), y=(3/4)x+1 
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The slope will be (3/4).
You have a point and the slope:
y-4=(3/4)(x-3)   : this is the pt-slope form
y=(3/4)x-(9/4)+(16/4)
y=(3/4)x+(7/4)   : this is the slope-intercept form
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cheers,
Stan H.