Question 718032
{{{2x(x+6)^4-x^2(4)(x+6)^3}}} divided by {{{(x+6)^8}}}, factor the dividend.  This is just like simplifying a fraction, no different.  


The dividend is {{{(x+6)^3(2x(x+6)-4x^2)}}}
={{{2x(x+6)^3(x+6-2x)}}}
={{{2x(x+6)^3(-x+6)}}}


Now you are looking for the dividend divided by the divisor:
{{{(2x(x+6)^3(-x+6))/((x+6)^8)}}}
={{{highlight(2x(-x+6)/((x+6)^5))}}}, before doing other multiplications.