Question 717976

We have a binomial experiment with p = 0.4 and n = 2. 





(1) Set up the probability distribution by showing all x values and their associated probabilities.


P(0)= (1-0.4)^2 = 0.36
P(1) = 2(0.4)(0.6) = 0.48
P(2) = 0.4^2 = 0.16 



(2) Compute the mean, variance, and standard deviation.


mean = np = 2(0.4) =0.8

variance = np(1-p) = 2(0.4)(0.6) = 0.48

sd = sqrt(variance) = sqrt(0.48)


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