Question 717953
The perimeter of a rectangle is 32ft. The length is 8 ft. longer than the width find the dimensions.  Write a system of linear equations solve the resulting system. Let x be the length and y be the width.


System:

2(x+y)=32

x = y+8

solution:

2(y+8+y)=32

2(2y+8)=32

2y+8=16

2y = 8

y = 4

x =  12

Answer:  legth = 12 width = 4