Question 717961
three timesa number added to a second number is 33. the first number added to three times the second number is 19. find the two numbers.

Let x and y those numbers:

3x+y = 33

x+3y = 19

Then  (multiply by 3 2nd eq)

3x+y = 33

3x+9y = 57

Then  (substracting them)

-8y = -24

y = 3

x = 10