Question 717822
This problem, in mathematical terms, is: How many combinations are possible when selecting 6 out of 9. The formula for this is:
{{{9!/(6!*3!)}}}
where n! is read "n factorial" and means 1 * 2 * 3 * ... * n<br>
Now we simplify:
{{{(1*2*3*4*5*6*7*8*9)/((1*2*3*4*5*6)*(1*2*3))}}}
{{{(cross(1*2*3*4*5*6)*7*8*9)/((cross(1*2*3*4*5*6))*(1*2*3))}}}
{{{(7*8*9)/(1*2*3)}}}
{{{(7*4*2*3*3)/(1*2*3)}}}
{{{(7*4*cross(2)*cross(3)*3)/(1*cross(2)*cross(3))}}}
{{{7*4*3)/1}}}
84<br>
So there are 84 different groups of 6 which can be chosen from a group of 9 players.