Question 717569
How much of "1+sinx(-sinx)-cosx(cosx)" is in the numerator of the fraction? Please put numerators and denominators in parentheses to make it clear. Clearly posted problems get quicker responses.<br>
If by chance all of "1+sinx(-sinx)-cosx(cosx)" is in the numerator (IOW, the expression is just one big fraction) then the answer is 0. Here's how:
{{{(1+sin(x)(-sin(x))-cos(x)(cos(x)))/(1+sin(x))^2}}}
Multiplying in the numerator:
{{{(1-sin^2(x)-cos^2(x))/(1+sinx)^2}}}
Since {{{1-sin^2(x) = cos^2(x)}}}:
{{{(cos^2(x)-cos^2(x))/(1+sinx)^2}}}
Subtracting:
{{{(0)/(1+sinx)^2}}}
which equals 0.<br>