Question 717610
{{{8^x=4}}}
Since 8 and 4 are both powers of 2, we can solve this quickly, easily and without logarithms:
{{{(2^3)^x = 2^2}}}
{{{2^(3x) = 2^2}}}
Two powers of 2 cannot be equal unless their exponents are equal.
{{{3x = 2}}}
{{{x = 2/3}}}