Question 717624
The maximum value is the vertex.

 the equation for a parabola can also be written in "vertex form":

{{{y = a(x-h)^2 + k}}}


you have {{{f(x) = 3-(x+2)^2}}} ...since {{{f(x) =y}}}, you have


{{{y= 3-(x+2)^2}}}....rearrange the terms on right side

{{{y=-(x+2)^2+3}}}...compare to {{{y = a(x-h)^2 + k}}} and you see that {{{a=-1}}}, {{{h=-2}}} and {{{k=3}}}

so, vertex is at ({{{-2}}},{{{3}}}) and it is maximum