Question 717617
{{{"f(x)"}}}{{{""=""}}}{{{35/(2x-1)}}}
<pre>
No denominator can ever equal to 0, so we must exclude any number(s)
from {{{(matrix(1,3,

-infinity,",",infinity))}}} for which a denominator equals to 0.

To find out what number(s) to exclude from {{{(matrix(1,3,

-infinity,",",infinity))}}} we set the denominator equal to 0, and
solve for x:

2x-1 = 0
  2x = 1
   x = {{{1/2}}}

So therefore the domain is:

{{{(matrix(1,3,

-infinity,",",1/2))}}}{{{U}}}{{{(matrix(1,3,

1/2,",",infinity))}}}

[Notice that the numerator 35 has no effect on the domain,
and it could have been anything.  We just ignore it.]

Edwin</pre>