Question 717598
Function Value Constraint
csc &#952; = 4 cot &#952; < 0 
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theta is in QII where x is negative and y is positive
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Since csc = r/y = 4, 
r = 4 and 
y = 1
Then x = -sqrt[16-1] = -sqrt(15)
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sin &#952; =  y/r = -1/4
cos &#952; =  x/r = -sqrt(15)/4
tan &#952; =  y/x = -1/sqrt(15)
csc &#952; =  r/y = -4
sec &#952; =  r/x = -4/sqrt(15)
cot &#952; =  x/y = -sqrt(15)
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Cheers,
Stan H.
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