Question 715744
The height, y, of a ball tossed into the air can be represented by the equation {{{ y= -x^2+10x+3 }}} , where x is the elapsed time. What is the equation of the axis of symmetry of this parabola?
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Vertex form of equation for a parabola that opens upward: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex
complete the square
y= -(x^2-10x+25)+25+3
y=-(x-5)^2+28
vertex(5,28)
axis of symmetry: x=5