Question 63262
Let Jill have x nickels and y dimes.
Then x + y = 50 ------------------------(1)

value of x nickels = 5x

value of y dimes = 10y

==> 5x + 10y = 350
Dividing throughout by 5 we have,

==> x + 2y = 70 -----------------------(2)

Subtracting eqns (2) and (1) we get,

y = 20
Plugging in y = 20 in (1)  we arrive that x = 30

Thus Jill had 30 nickels and 20 dimes.


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