Question 717353

Numbers are divisible by {{{9}}} if the {{{sum}}} of all the individual digits is evenly divisible by {{{9}}}. 


in {{{88_12}}} the {{{sum}}} of all the individual digits is {{{8+8+_+1+2=19+_}}} first number we can add to {{{19}}} to get a number divisible by {{{9}}} is {{{8}}} because {{{19+8=27}}} and {{{27}}} is divisible by {{{9}}}


so, your number is  {{{88812}}}