<PRE><B>Question 717197</B>
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If the secant is *[tex \LARGE \frac{9}{7}], then the hypotenuse is proportional to 9, and the adjacent leg is proportional to 7.  Hence the opposite leg is proportional to *[tex \LARGE \sqrt{32}\ =\ 4\sqrt{2}]


Now that you have the measures of the three sides, the remaining trigonometric functions are trival.  Don&#39;t forget to rationalize the denominators in the case of the cosecant and the cotangent.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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