Question 716550
Center (-2,1) Focus (-2,6) vertex (-2,4)
Find the standard form of the equation of each hyperbola satisfying the given conditions.
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Standard form of equation for a hyperbola with vertical transverse axis:
{{{(y-k)^2/a^2-(x-h)^2/b^2=1}}}, (h,k)=(x,y) coordinates of center
center: (-2,1)
a=3 (distance from center to vertex, (1 to 4 ))
a^2=9
c=5 (distance from center to focus, (1 to 6 ))
c^2=25
c^2=a^2+b^2
b^2=c^2-a^2=25-9=16
Equation of given hyperbola:
{{{(y-1)^2/25-(x+2)^2/16=1}}}