Question 717115
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The width is *[tex \LARGE w], the length is *[tex \LARGE w\ +\ 3], and the area is the length times the width: *[tex \LARGE w(x\ +\ 3)\ =\ w^2\ +\ 3w], and since the area is 108 mē,


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ w^2\ +\ 3w\ -\ 108\ =\ 0]


Solve the factorable quadratic for *[tex \LARGE w].  Discard the negative root as an absurdity.  Then calcualate *[tex \LARGE w\ +\ 3]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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