<PRE><B>Question 716727</B>
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In the 8 pints of 50% solution, there are 4 pints of water and 4 pints of developer.  In the end, you will have *[tex \LARGE x] pints of 16% solution, which will consist of *[tex \LARGE x\ -\ 8] pints of water that you added plus the 4 pints of water in the original solution plus the 4 pints of developer in the original solution, and since it is a 16% solution, we can say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ 0.16x\ =\ 4]


Solve for *[tex \LARGE x] to get the total amount of 16% solution, then subtract the 8 pints of 50% solution that you started with.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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