Question 716611
Common factors first, and getting that minus sign out of the way would be nice too.
{{{-c^4-c^3+56c^2=-c^2(c^2+c-56)}}}
If you cannot figure how to factor {{{c^2+c-56}}}
you can always resort to solving {{{c^2+c-56=0}}}
using the quadratic formula, but
{{{c^2+c-56=(c+8)(c-7)}}} so
{{{-c^4-c^3+56c^2=highlight(-c^2(c+8)(c-7))}}}