Question 716359
Let x = diameter of any random spherical bearing



If the circumference is 7.2, then the diameter is d = 7.2/pi = 2.2918


The absolute value inequality we'll use is


|x - t| <= e


where


t = target

e = error


So the target is roughly 2.2918 and the error is 0.1 (or less), so t = 2.2918 and e = 0.1


|x - t| <= e


|x - 2.2918| <= 0.1


-0.1 <= x - 2.2918 <= 0.1


-0.1 + 2.2918 <= x <= 0.1 + 2.2918


2.1918 <= x <= 2.3918


So the acceptable range of values for the diameter is between 2.1918 and 2.3918 (inclusive)