Question 716321
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The *[tex \LARGE y]-intercept is NOT 4.  An intercept is a point -- in this case a point in *[tex \LARGE \mathbb{R}^2].  Such points must be designated by an ordered pair, hence 4 is the *[tex \LARGE y]-coordinate of the the *[tex \LARGE y]-intercept, and the *[tex \LARGE y]-intercept is the point *[tex \LARGE (0,4)].


Step 1 is to calculate the slope of the line represented by the given equation.  Since this equation is in Standard Form, divide the opposite of the coefficient on *[tex \LARGE x] by the coefficient on *[tex \LARGE y] to calculate the slope.


Parallel lines have identical slopes, so you now have the slope of the desired line.


Step 2: Use the point-slope form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given *[tex \Large y]-intercept point and *[tex \Large m] is the slope calculatedd above.


Step 3:  Solve the resulting equation for *[tex \LARGE y] in terms of everything else to put the equation into slope-intercept form. 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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