Question 63173
{{{2/z^2}}} - {{{3/2}}}  
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{{{2/5z^2}}} + {{{1/3z}}}
:
Get the numerator into a single fraction, common denominator is 2z^2
giving you:
{{{2/z^2}}} - {{{3/2}}} = {{{(2(2) - 3z^2)/2z^2}}} = {{{(4 - 3z^2)/2z^2}}}
:
Do the same with the denominator, common denominator 15z^2 
{{{2/5z^2}}} + {{{1/3z}}} = {{{(3(2) + 5z)/15z^2}}} = {{{(6 + 5z)/15z^2}}}
:
Remember when we divide we invert the dividing fraction and mult so we have:
{{{(4 - 3z^2)/2z^2}}} * {{{15z^2/(6+5z)}}} 
:
We can cancel the z^2 which are in the single terms:
{{{(4 - 3z^2)/2}}} * {{{15/(6+5z)}}} = {{{(15(4-3z^2))/(2(6+5z))}}} = {{{(60-45z^2)/(12+10z)}}} about as far as we can go with it.
:
Could you follow all this? Study each step and it will make sense to you. good luck!