Question 716064
{{{3^x=4-3*3^(-x)}}}
since {{{3^(-x)=1/3^x}}}
{{{3^x=4-3/3^x}}}
Substitute {{{u=3^x}}}, {{{u>0}}}
{{{u=4-3/u}}}
{{{u^2-4u+3=0}}}
{{{(u-3)(u-1)=0}}}
{{{u-3=0}}} or {{{u-1=0}}}
{{{u=3}}} or {{{u=1}}}
{{{3^x=3}}}
{{{3^x=3^1}}}
{{{x=1}}}
or
{{{3^x=3}}}
{{{3^x=3^0}}}
{{{x=0}}}
Answer: x=0, x=1