Question 715969
<pre>
y = {{{(x-5)/(x^2+4x+3)}}}

Factor the denominator:

y = {{{(x-5)/((x+3)(x+1))}}}

There are no holes because the numerator and the denominator
have no common factors.

Therefore the equations of the vertical asymptotes are found 
by setting the denominator = 0

(x+3)(x+1) = 0

x+3=0;  x+1=0
  x=-3;   x=-1

It has x-intercept (5,0) and y-intercept (0,{{{-5/4}}}).
The green lines are the vertical asymptotes:

{{{drawing(400,400,-10,10,-5,15,
graph(400,400,-10,10,-5,15,(x-5)/(x^2+4x+3)),green(line(-3,-15,-3,15),
line(-1,15,-1,-15)) )}}}

Edwin</pre>