Question 715820
Angles of 55 degrees and 125 degrees cannot possibly be the interior angles of a triangle,
because the measures of all 3 interior angles must add to 180 degrees,
and 55 degrees plus 125 degrees add to 180 degrees (55+125=180),
not leaving any room for a third angle.
 
However, if the 125 degree angle is an exterior angle, like this
{{{drawing(300,200,-60,60,-5,75,
triangle(-45.89,0,45.89,0,0,65.53),
line(45.89,0,60,0),
locate(-40,10,55^o),locate(46,10,125^o)
)}}} then the other interior base angle measures {{{180^o-125^o=55^o}}}
just like the left one, making it an isosceles triangle.
That is nice to know, but not related to the answer.
If the drawing is like mine,
the two interior angles at the base add up to {{{55^o+55^o=110^o}}}
and the third angle should measure {{{180^o-110^o=highlight(70^o)}}} .
An angle measuring {{{70^o}}} is smaller than a right angle ({{{90^o}}})
and because of that is called an {{{highlight(acute)}}} angle.