Question 715807


the volume of a cylinder:

{{{V=r^2*pi*h}}}

 and surface area of a cylinder:

{{{A=2r^2*pi+2*pi*r*h}}}

given: 

{{{h= 6m}}} 

{{{d=4m}}}... if  diameter {{{d=4m}}}, then radius {{{r=2m}}}


{{{V=r^2*pi*h}}}....plug in given values

{{{V=(2m)^2*3.14*6m}}}

{{{V=4m^2*3.14*6m}}}

{{{highlight(V=75.36m^3)}}}



{{{A=2r^2*pi+2*pi*r*h}}}...plug in given values

{{{A=2(2m)^2*3.14+2*3.14*2m*6m}}}

{{{A=2*4m^2*3.14+2*3.14*2m*6m}}}

{{{A=8m^2*3.14+75.36m^2}}}

{{{A=25.12m^2+75.36m^2}}}

{{{highlight(A=100.48m^2)}}}