<PRE><B>Question 715705</B>
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2i  |  1   0   4
    |     2i  -4
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       1  2i   0
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Hence, *[tex \LARGE \frac{x^2\ +\ 4}{x\ -\ 2i}\ =\ x\ +\ 2i]


Check:  *[tex \LARGE (x\ -\ 2i)(x\ +\ 2i)\ =\ x^2\ +\ 2ix\ -\ 2ix\ -\ (2i)^2\ =\ x^2\ -\ (-4)\ =\ x^2\ +\ 4]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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