Question 715676
{{{n}}}=length of shorter side
The lengths of the other two sides must be
{{{n+1}}} and {{{n+2}}}.
The perimeter is
{{{n+(n+1)+n+2)=12}}}
Re-arranging, we get
{{{(n+n+n)+(1+2)=12}}}
{{{3n+3=12}}} --> {{{3n=12-3}}} --> {{{3n=9}}} --> {{{n=9/3}}} --> {{{highlight(n=3)}}}
Then {{{n+1=3+1}}} --> {{{highlight(n+1=4)}}} and
{{{n+2=3+2}}} --> {{{highlight(n+2=5)}}}