Question 715439
{{{(2n-1)v^2-2nv+1=0}}}

Recognize that this is in general form for quadratic equation in variable, v.  You CAN use the general solution.


{{{v=(2n-sqrt(4n^2-4*(2n-1)))/(2(2n-1))}}}, or {{{v=(2n+sqrt(4n^2-4*(2n-1)))/(2(2n-1))}}} and continue to simplify from that.