Question 715445
I am trying to expand a natural log of a fraction. I am looking at the ln of (x^2-1 over x^4). The textbook also points out that x>1 although I don't know why that information is important to solve this. The answer I came up with was ln(x^2-1)-4lnx  but webassign.net says it is wrong. I am stumped and my stupid textbook doesn't explain what I'm doing wrong.

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{{{ln((x^2-1)/x^4) = ln(x^2-1) - 4ln(x)}}}
Maybe you're expected to factor the numerator?
= {{{ln(x+1) + ln(x-1) - 4ln(x)}}}