Question 715427
LET X & 2X BE THE SPEED OF THE 2 TRAINS.
D=RT
288=(X+2X)3
288=3X*3
288=9X
X=288/9
X=32 SPEED OF THE SLOWER TRAIN
2*32=64 SPEED OF THE FASTER TRAIN.
PROOF:
288=(32+64)*3
288=96*3
288=288