Question 715354
To make all spaces the same, the space before each stone plus the diameter of the stone would have to be
{{{44/15}}}
That is about {{{3}}} .
Using a {{{2}}} unit spacing between stones, each 1-unit wide stone plus the extra 2 units before it would take up {{{3}}} units of space.
So {{{14}}} stones plus the spaces before each one would take up
{{{3*14=42}}} units.
That leaves {{{44-42=2}}} units of space for the first stone plus the space between that stone and the house, which would be {{{2-1=1}}} unit of space.
 
That takes care of the math problem, and the size of those "units" in terms of millimeters (or inches, or whatever) is not needed to solve the math problem.
However, that size makes me worried about that elderly neighbor.
If one unit is 500mm, which is 0.5 meters, the space between stones will be 1 meter, and that is way too wide a gap for an elderly lady to jump over.
Even 500mm=0.5m is an almost uncomfortably long step for me.
(My height is about average and I am not young, but I am still agile enough to chase grandchildren).
If I had to walk to a bird feeder, over rain-slick stones, I would like them even closer than 0.5m.