Question 715158
 

a)the surface area of one of them

the shorter has the surface area:

{{{Surface _area = 2(pi)r^2 + height * 2(pi)r}}}....{{{r=3cm}}} and {{{h=2cm}}}

{{{Surface_ area = 2(3.14)*3^2 + 2* 2*(3.14)*3}}}

{{{Surface_ area = 2(3.14)*9 + 4*(3.14)*3}}}

{{{Surface_ area = 56.52 + 37.68}}}

{{{Surface_ area = 94.2cm^2}}}



b)height of taller cylinder

it has a radius of {{{r=1cm}}} and same surface area

{{{94.2= 2(pi)*1^2 + height * 2(pi)*1}}}

{{{94.2= 2(3.14)*1^2 + height * 2(3.14)*1}}}

{{{94.2= 6.28 + height * 6.28}}}

{{{94.2- 6.28= height * 6.28}}}

{{{87.92= height * 6.28}}}

{{{87.92/6.28= height }}}

{{{14cm= height }}}