Question 715123
Find the hypotenuse of a triangle whose sides are (x+1) (x+3) and x
----------
x+3 is the largest, so it's the hypotenuse
{{{(x+3)^2 = x^2 + (x+1)^2 = x^2 + x^2 + 2x + 1}}}
{{{x^2 + 6x + 9 = 2x^2 + 2x + 1}}}
{{{x^2 - 4x - 8 = 0}}}
Solve for x, etc