Question 714881
{{{drawing(300,150,-1,17,-2,7,
line(0,0,12,0),line(3,5.2,15,5.2),
line(0,0,3,5.2),line(12,0,15,5.2),
green(line(3,0,3,5.2)),rectangle(3,0,2.5,0.5),
locate(3.2,3,h),locate(0.8,3.2,6),locate(0.5,1.5,60^o),
arrow(5.5,-1,0,-1),arrow(6.5,-1,12,-1),locate(5.6,-0.5,12)
)}}} {{{h=6*sin(60^o)=6*(sqrt(3)/2)=3sqrt(3)}}} {{{area =12*h=12*3sqrt(3)=highlight(36sqrt(3))}}}=approx.{{{highlight(62.4)}}}