<PRE><B>Question 714247</B>
ACCORDING TO THE GIVEN CONDITION
SHORTEST SIDE IS EQUAL TO THE = A= X
2ND SIDE IS EQUAL TO  = B =2X
3RD SIDE IS EQUAL TO = C =16 + X

IN MATHEMATICALLY,
 PERIMETER = A +B +C
 PERIMETER = X + +2X + (16 +X)
 80 = 4X + 16
4X = 80-16
4X = 64
          X = 64/4
          X = 16
SHORTEST SIDE IS EQUAL TO THE = A= X = 16
2ND SIDE IS EQUAL TO  = B =2X = 2*16 = 32
3RD SIDE IS EQUAL TO = C =16 + X = 16 + 16 = 32

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